Here,
an = 5 – 11n ------------- (1)
Taking n = 1 in eqⁿ (1), we get
➡ a1 = 5 – 11(1)
➡ a1 = 5 – 11
➡ a1 = –6
Now, Taking n = 2 in eqⁿ (1), we get
➡ a2 = 5 – 11(2)
➡ a2 = 5 – 22
➡ a2 = – 17
Now, Taking n = 3 in eqⁿ (1), we get
➡ a3 = 5 – 11(3)
➡ a3 = 5 – 33
➡ a3 = – 28
Now, we get the AP :-
–6, – 17, – 28,..........
Here, the common difference is
➡ d = –17 – (–6)
➡ d = –17 + 6
➡ d = –11