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Question

If the pth and qth terms of a G.P. are q and p respectively, show that (p+a)th term is (qppq)1pq.

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Solution

nth term of GP = arx1

pth term = q=a.rp1

qth term = p=a.rq1

qp=rpq

r=(qp)1pq

a=p(pq)1qpq

p+qthterm=p(qp)1qpq(qp)p+q1pq

P(qp)1q+p+q1pq

P(qp)ppq

qppqpppq1

qppqpppq

(qppq)1pq


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