If the points p(-3,9) ,Q(a,b) ,R(4,-5)are collinear and a+b=1.Find the value of a & b.
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Solution
Given slope of PQ=slope of QR b-9/a+3=-5-b/4-a b-9(4-a)=-5-b(a+3) 4b-ab-36+9a=-5a-15-ab-3b 4b+3b+9a+5a-36+15=0 7b+14a-21=0 7(2a+b-3)=0 2a+b-3=0 2a+b=3..................(1) a+b=1..............(2) (1)-(2)=>a=2 substitute a=2 in (2) 2+b=1 b=-1