If the pth term of an AP is q and its qth term is p then its mth term is:
pth term = a + (p – 1) d = q ... (i)
q th term = a + (q – 1) d = p ... (ii)
Subtracting (ii) from (i)
(p – 1) d – (q – 1) d = q – p
->pd – d – qd + d = q – p
->d (p – q) = q – p
-> d = -1a = q – (p – 1)d = q + (p – 1)
So, mth term = q + p – 1 – (m – 1) = q + p – 1-m + 1 = p + q – m
Hence option (b)
Alternatively, use assumption
Let the first term=2 and the 2nd term=1, therefore p=1 and q=2
Let m=3
Thus, 3rd term=0. Substitute the values of p,q and m in the answer options and look for 0. Only option (b) gives this value