U ={x | x ∈ N , x < 10}= {1,2,3,4,5,6,7,8,9}
A= {x | x ∈ N , 2 ≤ x < 6}= {2, 3, 4, 5}
Then, A’= {1, 6, 7, 8, 9} [Since The Complement of a set A is the set of all elements of U that are not in A.]
∴ (A′)′= {2, 3, 4, 5} [The Complement of a set A’ is the set of all elements of U that are not in A’.]
Hence (A′)′= A= {2, 3, 4, 5}
Correct Option: c) {2, 3, 4, 5}