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Question

If a=2^i+3^j4^k,b=^i+^j+^k and c=4^i+3^k, then |a×(b×c)|=

A
10
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B
1
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C
2
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D
129
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Solution

The correct option is D 129
a×(b×c)
=b(a.c)c(a.b)
=b(812)c(2+34)
=4bc
=(4(i+j+k)+4i+3k)
=(8i+4j+4k)
Now |(8i+4j+7k)|
=64+16+49
=80+49
=129

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