If →a=4^i−^j+^k and →b=2^i−2^j+^k, then find a unit vector parallel to the vector →a+→b.
As →a+→b=6^i−3^j+2^k
Unit vector parallel to →a+→b is 1√36+9+4(6^i−3^j+2k) i.e., 17(6^i−3^j+2^k).