If - p-q-2-p-q- -3 and a-3p-q- -b-p- -3q- then for the parallelogram with sides a-b- I- Lengths of sides are -28- -52II- Lengths of diagonals are -112-48

The correct option is C Both I II are true |a| = |3p q| = √(9p^2 + q^2 6|p||q|cos60^0) = √(36 + 4 12) = √(28) |b| = |p + 3q| = √(q^2 + 9p^2 ...

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Section Formula

If | p⃗|=|q...

Question

If $| \to p | = | \to q | = 2, (\to p, \to q) = π / 3$ and $\to a = 3 \to p - \to q, \to b = \to p + 3 \to q$ , then for the parallelogram with sides $\to a, \to b$
I: Lengths of sides are $\sqrt{28}, \sqrt{52}$
II: Lengths of diagonals are $\sqrt{112}, \sqrt{48}$

Only I is true

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Only II is true

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Both I & II are true

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Neither l nor ll are true

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\to a = 3 \to p - \to q, \to b = \to p + 3 \to q

| \to p | = | \to q | = 2

\to p

\to q

\frac{π}{3}

\to a, \to b, \to c

\to p, \to q, \to r

(\to a \times \to p) + (\to b \times \to q) + (\to c \times \to r)

\to p

\to q

30^{o}

\to a = \to p + 2 \to q; \to b = 2 \to p + \to q

\to a, \to b, \to c

\to p, \to q, \to r

\to p = \frac{\to b \times \to c}{[\begin{matrix} \to b & \to c & \to a \end{matrix}]}

\to q = \frac{\to c \times \to a}{[\begin{matrix} \to c & \to a & \to b \end{matrix}]}

\to r = \frac{\to a \times \to b}{[\begin{matrix} \to a & \to b & \to c \end{matrix}]}

(\to a + \to b) . \to p + (\to b + \to c) . \to q + (\to c + \to a) . \to r

If $\to A$ + $\to B$ = $\to P$ and $\to A$ $\times$ $\to B$ = $\to Q$ then

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