If x-b-c-b- and x-a- then x- is equal to

The correct options are B ( b⃗×c⃗ )×a⃗b⃗.a⃗ C a⃗× ( c⃗×b⃗ )a⃗.b⃗ x⃗×b⃗=c⃗×b⃗ .... 1Pre multiplying both sides of 1 by a⃗ , we get a⃗×(x ...

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Applications of Dot Product

If x⃗×b⃗=c⃗...

Question

If $\to x \times \to b = \to c \times \to b$ and $\to x ⊥ \to a$ , then $\to x$ is equal to

\frac{\to b \times (\to a \times \to c)}{\to b . \to c}

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\frac{(\to b \times \to c) \times \to a}{\to b . \to a}

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\frac{\to a \times (\to c \times \to b)}{\to a . \to b}

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None of these

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Similar questions

\to a \times (\to b \times \to c) + \to b \times (\to c \times \to a) + \to c \times (\to a \times \to b) = \to x \times \to y

[\begin{matrix} \to a & \to b & \to c \end{matrix}] = 1

\frac{\to a . \to b \times \to c}{\to c \times \to a . \to b} + \frac{\to b . \to c \times \to a}{\to a \times \to b . \to c} + \frac{\to c . \to a \times \to b}{\to b \times \to c . \to a}

[\to a \to b \to c] = 2

\frac{\to a . (\to b \times \to c)}{(\to c \times \to a) . \to b} + \frac{\to b . (\to c \times \to a)}{(\to a \times \to b) . \to c} + \frac{\to c . (\to a \times \to b)}{(\to b \times \to c) . \to a} =

(\to a \times \to b) \times \to c = \to a \times (\to b \times \to c)

\to a, \to b

\to c

\to a . \to b \neq 0, \to b . \to c \neq 0

\to a

\to c

| \to a | = 3, ∣ ∣ \to b ∣ ∣ = 4, | \to c | = 5, \to a ⊥ (\to b + \to c), \to b ⊥ (\to c + \to a)

\to c ⊥ (\to a + \to b)

\sqrt{2} ∣ ∣ \to a + \to b + \to c ∣ ∣

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