If w1, w2, w3 and w4 are work done in isothermal, diabatic, isobaric and isochoric reversible processes, respectively then the correct sequence (for expansion) would be:
A
w1<w2<w3<w4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
w3=w2=w1=w4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
w3<w2<w4<w1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
w3>w1>w2>w4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is Dw3>w1>w2>w4
Since W=∫PdV
where ∫PdV is simply the area enclosed by the P−V curve under volume axis. For the given curve, it may be observed that the area enclosed by the isobaric process is maximum followed by the isothermal, adiabatic and Isochoric process.