If x2+1x2=27, find x-1x.
Compute the required value.
As we know that, a-b2=a2+b2-2ab.
⇒x-1x2=x2+1x2-2x×1x⇒x-1x2=27-2⇒x-1x2=25
Take square root on both sides.
⇒x-1x=±25
Hence, the value of x-1x is ±5.