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Inverse of a Function

If x2+4 y2-8 ...

Question

If $x^{2} + 4 y^{2} - 8 x + 12 = 0$ is satisfied by real values of x and y then 'y' $ϵ$

[2, 6]

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[2, 5]

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[-1, 1]

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[-2, -1]

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Solution

The correct option is C
[-1, 1]

$x^{2} - 8 x + (4 y^{2} + 12) = 0$ is a quadratic in 'x' , 'x' is real then discriminate $\geq$ 0

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