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Question

If x2+y2=t1t and x4+y4=t2+1t2,then x3ydydx equals

A
- 1
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B
0
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C
1
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D
None of these
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Solution

The correct option is C 1
x2+y2=t1t
On squaring both the sides
=x4+y4+2x2y2 = t2+1t22
Given that -
x4+y4=t2+1t2
x2y2=1
x2.2ydydx+y2.2x=0
x3ydydx=x2y2=1

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