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B
0
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C
1
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D
None of these
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Solution
The correct option is C 1 x2+y2=t−1t On squaring both the sides =x4+y4+2x2y2 = t2+1t2−2 Given that - x4+y4=t2+1t2 ∴x2y2=−1 ⇒x2.2ydydx+y2.2x=0 ⇒x3ydydx=−x2y2=1