If |x+3|−|x−4|=4, then x=
Find the number of values of x satisfying
3x−3≤7x+5 and 5−x≥(x4)−(54),where x ϵ N.
6−5 x 5−2 x 63 x 5m x 6n = 1, then m + n will be
Using componendo and dividendo find out the value of x. √3x+4+√3x−5√3x+4−√3x−5=9