If (x5−9x2+12x−14) is divided by (x–3), then the remainder is:
Given polynomial is: f(x)=x5−9x2+12x−14 By Remainder Theorem, f(3) gives the remainder when f(x) is divided by (x–3). f(3)=35–9×(3)2+12×3–14 f(3)=243−81+36−14 f(3)=184
If (x5-9x2+12x-14) is divided by (x – 3), the remainder is
If x5 - 9x2 + 12x -14 is divisible by x-3, what is the remainder?