If x = (7 + 21 + 35 + 49 … + 119), y = (4 + 12 + 20 + … + 44) and z = x – y, then 3√2z−117equals यदि x = (7 + 21 + 35 + 49 … + 119), y = (4 + 12 + 20 + … + 44) तथा z = x – y, तब 3√2z−117 बराबर है
The distance between the planes 3x - 2y + 6z + 21 = 0 and - 6x + 4y - 12z + 35 = 0 is: