If x= 7+40, find the value of x+ 1/x

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x = 7 + 4 \sqrt{3}

(\sqrt{x} + \frac{1}{\sqrt{x}})

x

(20 x + 3) - (5 x - 7) = 40

x - \frac{1}{x} = 7

x^{3} - \frac{1}{x^{3}}

If x=7+√3, find the value of √x+1\√x

If $x + \frac{1}{x} = 7$ then find the value of $x^{3} + \frac{1}{x^{3}}$

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