If x - a cos t -logtan t -2- y - a sin t- then show that t - dx -tan t

Dx/dt=a [ sin t+1/tan t/2 sec^2 t/21/2 ] =a [ sin t+1/sin t ] a [ cos^2t/sin t ] dy/dt=a cos t ∴ dy/dx=tan t ...

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Implicit Differentiation

If x = a cos ...

Question

If $x = a (c o s t + l o g t a n \frac{t}{2}), y = a s i n t$ , then show that $\frac{d y}{d x} = t a n t .$

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x = a (cos t + log tan \frac{t}{2}), y = a sin t

\frac{d y}{d x} =

Find $\frac{d y}{d x}, x = a (cos t + log tan \frac{t}{2}), y = a sin t$

x = a (cos t + log tan \frac{t}{2}), y = a sin t

\frac{d^{2} y}{d x^{2}}

t = \frac{π}{3}

x = a (cos t + l o g tan \frac{t}{2})

y = a sin t

\frac{d^{2} y}{d x^{2}}

t = \frac{π}{3}

x = a (cos t + log tan \frac{t}{2}), y = a sin t

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