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Question

If x = acost, y = asint, then d2ydx2 at t=π4 is


A

a22

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B

a22

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C

22a

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D

22a

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Solution

The correct option is D

22a


Clearly x2+y2=a2 and y(π4)=a2,(π4)=1
2x+2yy1=0y1=xy,soy1(π4)=1.Nowx+yy1=01+y21+yy2=0
y2(π4)=1+(y1(π4))2y(π4)=22a


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