If x+ax = 1, then the value of x2+x+ax3−x2 is
-1/a
-2/a
-3/a
Can't be determined
None of these
x + ax = 1
⇒ x2 + a = x....(1)
⇒ x2 - x = -a....(2)
Now, (x2 +x+a)/(x3 -x2 ) = 2x/[x(x2 -x)]
= 2/(-a) [From (1) and (2)]
= -2/a