log1075=2−2x+y.
Explanation:
Given that, log10=2=x, and log103=y.
We will use, in what follows, the familiar Rules of Log.Fun
We have,
log1075=log10(3×52),
log103+log1052
=y+2log105................... [∵,log103=y, given],
=y+2log10(10÷2),
=y+2{log1010−log102},
=y+2(1−x).................... [∵,log102=x, given].
⇒log1075=2−2x+y.