If x=3√2+√3, then x3+1x3=
2
4
8
9
x=(2+√3)13⇒x3=2+√3
∴1x3=12+√3=1×(2−√3)(2+√3)(2−√3)
=2−√3(2)2−(√3)2=2−√34−3
(Rationalising the denominator)
=2−√31=2−√3
∴ x3+1x3=2+√3+2−√3=4
If x=2+√3, then x3+1x3 = __.