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Algebraic Identities

If x+y=-2, th...

Question

If x+y=-2, then $x^{3}$ + $y^{3}$ +8 equals

A

(x+y+2)³

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B

zero

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C

6xy

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D

-6xy

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Solution

The correct option is C
6xy

$x^{3}$ + $y^{3}$ = ${(x + y)}^{3}$ – 3xy (x + y)

$x^{3}$ + $y^{3}$ + 8 = ${(- 2)}^{3}$ – 3xy (-2) + 8

= -8 + 6xy + 8

= 6xy

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Similar questions

Q. If x+y+2=0 then

x^{3} + y^{3} + 8

x + y + 2 = 0

then find the value of

x^{3} + y^{3} + 8

\frac{x}{y} + \frac{y}{x}

\neq

x^{3} + y^{3}

+3xy(x + y) is equal to:

x + y = 5, x^{3} + y^{3} = 35

x - y

x + y - 1 = 0

x^{3} + y^{3} - 1

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