If x - y -0- -2 and cos x sin y -1-sin y-tan z- then z can lie inA- 0- -2B- -2- -C- - 3 -2D- 3 -2- 2 -

The correct options are A (0, π/2) C (π, 3 π/2) L.H.S gt; 0 and hence R.H.S gt; 0 ...

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Theorems for Continuity

If x , y ϵ0, ...

Question

If $x, y ϵ (0, \frac{π}{2})$ and $(c o s x)^{s i n y + \frac{1}{s i n y}} = t a n z,$ then z can lie in

$(0, \frac{π}{2})$

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$(\frac{π}{2}, π)$

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$(π, \frac{3 π}{2})$

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$(\frac{3 π}{2}, 2 π)$

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