wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If x+y+z=6,xy+xz+yz=11,xyz=6,
then xyz+yxz+zxy equals

A

73

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

136

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

53

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

611

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

73


xyz+yzx+zxy=x2+y2+z2xyz
=(x+y+z)2(xy+yz+zx)xyz
=622×116=146=73


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Fundamental Laws of Logarithms
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon