If xy+yz+xz=0, then find 1/(x^2-yz)+1/(y^2-xz)+1/(z^2-xy)

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x^{2} + x y + x z = 135, y^{2} + y z + x y = 351

z^{2} + x z + y z = 243

x^{2} + y^{2} + z^{2} = ?

x^{2} + y^{2} + z^{2}

x^{2} + x y + x z = 135, y^{2} + y z + y x = 351

z^{2} + z x + z y = 243

x^{2} + x y + x z = 18

y^{2} + y z + y z + 12 = 0

z^{2} + z x + z y = 30

x^{2} + x y + x z = 135, y^{2} + y z + x y = 351

z^{2} + z x + z y = 243

(x, y, z > 0)

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