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Question


If z=x1/25y1/25x1/20+y1/20, then the value of

xzx+yzy is

A
z100
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B
z
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C
z2
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D
z4
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Solution

The correct option is A z100

zx=125x2425(x1/20+y1/20)120x1920(x1/25y1/25)(x1/20+y1/20)2

xzx=125x1/25(x1/20+y1/20)120x1/20(x1/25y1/25)(x1/20+y1/20)2


yzy=125y1/25(x1/20+y1/20)120y1/20(x1/25y1/25)(x1/20+y1/20)2

xzx+yzy=(125120)z

=z100


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