Question

If $z=\frac{(\sqrt{3}+i{)}^3(3i+4{)}^2}{(8+6i{)}^2}$, then |$z$| is equal to

• A. 0
• B. 1
• C. 2
• D. 3

Answer 1

The correct option is C

2

$Z=\frac{(\sqrt{3}+i{)}^3(3i+4{)}^2}{4(3i+4{)}^2}$$\Rightarrow z=2.cis\frac{\pi }{2}$

$\therefore z=2i$

$\Rightarrow |z|=2$