If z = ilog(2−√3), then value of cos z is ______ [use e(logeA)=A]
Z = ilog(2−√3)
eiz=ei[ilog(2−√3)]
= e−log(2−√3)=12−√3
e−iz=e−i(ilog(2−√3))=2−√3
Cos z = eiz+e−iz2
= [12−√3+2−√3]12
= [2+√3+2−√3]12 [∵12−√3=2+√3]
= 2