Ii Show that - cos 38- cos 52- - sin 38- sin 52- - 0

Cos 38^∘ cos 52^∘ sin 38^∘ sin 52^∘ = cos (90^∘ 52^∘) cos (90^∘ 38^∘) sin 38^∘ sin 52^∘ = sin 52^∘ sin 38^∘ sin 38^∘ sin 52^∘= 0 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Complementary Trigonometric Ratios

ii Show that ...

Question

Question 2 (ii)
Show that :
$c o s 38^{\circ} c o s 52^{\circ} - s i n 38^{\circ} s i n 52^{\circ} = 0$

Open in App

Solution

Suggest Corrections

Similar questions

c o s 38^{\circ} c o s 52^{\circ} - s i n 38^{\circ} s i n 52^{\circ} = 0

cos 38^{\circ} cos 52^{\circ} - sin 38^{\circ} sin 52^{\circ} = 0

c o s 38^{\circ} c o s 52^{\circ} - s i n 38^{\circ} s i n 52^{\circ} = 0

tan 48^{\circ} tan 23^{\circ} tan 42^{\circ} tan 67^{\circ} = 1

cos 38^{\circ} cos 52^{\circ} - sin 38^{\circ} sin 52^{\circ} = 0

cos 38^{\circ} cos 52^{\circ} - sin 38^{\circ} sin 52^{\circ}

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program