Question

(ii) $t_{n=2n-5}$

Answer 1

(ii) We have the n^th term of a sequence as t_n = 2n – 5.
To find the first five terms of the sequence, we need to take n = 1, 2, 3, 4 and 5.

For n = 1, we have:
t₁ = 2 × 1 – 5 = 2 – 5 = –3

For n = 2, we have:
t₂ = 2 × 2 – 5 = 4 – 5 = –1

For n = 3, we have:
t₃ = 2 × 3 – 5 = 6 – 5 = 1
For n = 4, we have:
t₄ = 2 × 4 – 5 = 8 – 5 = 3

For n = 5, we have:
t₅ = 2 × 5 – 5 = 10 – 5 = 5

Thus, the first five terms of the sequence are –3, –1, 1, 3 and 5.