Question 81 (iii)
Add :
xy2z2+3x2y2z−4x2yz2,−9x2y2z+3xy2z2+x2yz2
We have,
(xy2z2+3x2y2z−4x2yz2)+(−9x2y2z+3xy2z2+x2yz2)
=xy2z2+3x2y2z−4x2yz2−9x2y2z+3xy2z2+x2yz2
=(xy2z2+3xy2z2)+(3x2y2z−9x2y2z)+(−4x2yz2+x2yz2)
[grouping like terms]
=4xy2z2−6x2y2z−3x2yz2