Question

Question 98(iii)

Solve the following:

$\frac{49\times z^{-3}}{7^{-3}\times 10\times z^{-5}}(z\ne 0)$

Answer 1

$\frac{49\times z^{-3}}{7^{-3}\times 10\times z^{-6}}=\frac{(7{)}^2\times z^{-3}}{7^{-3}\times 10z^{-5}}=\frac{(7{)}^{2+3}\times z^{-3+5}}{10}=\frac{(7{)}^5{z}^2}{10}=\frac{7^5}{10}{z}^2$