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Question

In a ΔABC, if sin2 A+sin2 B=sin2, C show that the triangle is right angled.

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Solution

Let sin A=ak, sin B=bk, sin C=cksin2 A+sin2 B=sin2 C k2a2+k2b2=k2c2 [Using sine rule] a2+b2=c2Since the triangle satisfies the Pythagoras theoram, therefore it is right angled.


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