Question

In a $\Delta$PQR, right angled at Q, PQ$=$ 24 cm and QR$=$ 7 cm. S is the mid point of PR, then RS is :

• A. 3.5cm
• B. 12cm
• C. 25cm
• D. 12.5cm

Answer 1

Answer: (D)

12.5cm

In $△PQR$

${\left(PQ\right)}^2+{\left(QR\right)}^2={\left(PR\right)}^2{\left(24\right)}^2+{\left(7\right)}^2={\left(PR\right)}^2\Rightarrow {\left(PR\right)}^2=576+49=625\Rightarrow PR=25$

Now $S$ is the mid point of $PR$

$\therefore RS=\frac{PR}{2}=\frac{25}{2}=12.5cm$