MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Power in an AC Circuit

In a series R...

Question

In a series RLC circuit, the r.m.s voltage across the resistor and the inductor are respectively 400V and 700V. If the equation for the applied voltage is e=500\ast2^1/2sinwt, then the peak voltage across the capacitor is(1)1200V(2)1200\ast2^1/2V(3)400V(4)400\ast2^1/2V

Open in App

Solution

Suggest Corrections

thumbs-up

41

Similar questions

Q. Voltage across inductor, capacitor and resistor in a series LCR ac circuit are 20V, 60 V and 70 V respectively peak value of the applied voltage is:-

Q. In a series LCR circuit the voltage across an inductor, capacitor and resistor are 20V, 20V and 40V respectively. The phase difference between the applied voltage and the current in the circuit is

A C

voltage is applied across a series combination of

L

R

. If the voltage drop across the resistor and inductor are

20 V

15 V

respectively, then applied peak voltage is :

L - C - R

circuit, current in the circuit is

11 A

when the applied voltage is

220 V

. Voltage across the capacitor is

200 V

. If value of resistor

20 Ω

, then the voltage across the unknown inductor is

Q. A resistor of

40 Ω

, an inductor of

5 / π H

and a capacitor of

50 / π μ F

are connected in series across a source of alternating voltage of

140 sin 100 π t

Volts. Find the r.m.s voltage across the resistor, the inductor and the capacitor. Is algebraic sum of these voltages more than the source voltage? If yes, resolve the paradox

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Electrical Power in an AC Circuit

PHYSICS

Watch in App

explore_more_icon

Explore more

Power in an AC Circuit

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon