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Construct Triangle When Its Base, Difference of the Other Two Sides and One Base Angle Are Given

In a triangle...

Question

In a triangle ABC, ∠B = 70°, Find ∠A + ∠C.

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Solution

In ΔABC, ∠A + ∠B + ∠C = 180° (Sum of angles of a triangle)

∠A + 70° + ∠C = 180° (Given ∠B = 70°)

∠A + ∠C = 180° − 70°

∴∠A + ∠C = 110°

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∠ B = 70^{o} .

∠ A + ∠ C (i n d e g r e e)

△ A B C, ∠ A + ∠ B = 70^{\circ}

∠ B + ∠ C = 135^{\circ}

In the given isosceles triangle ABC, AB = AC, $∠ A B C$ = 70°. Find $∠$ BAC.

△ A B C

△ P Q R, ∠ A = 30^{o}, ∠ B = 70^{o}, ∠ P = 70^{o}, ∠ Q = 80^{o}

A B = R P,

∠ B = 70^{o}

∠ A

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Construct Triangle When Its Base, Difference of the Other Two Sides and One Base Angle Are Given

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