Question

In $△ABC$ and $△PQR$, if $\angle A=90°$, $AC$ $=6cm$, $BC=9cm$, and $\angle Q=90°$, $PR=9cm$,$PQ=6cm$, then using RHS criterion we have $△ABC\cong △$_______.

Answer 1

In RHS criterion:

Two right-angled triangles are congruent if the hypotenuse and a leg of one triangle are equal to the hypotenuse and the corresponding leg of the other. This condition is called the RHS criterion.

Given as $\angle A=90°$, $AC$ $=6cm$, $BC=9cm$ and $\angle Q=90°$, $PR=9cm$,$PQ=6cm$

Therefore

$AC$ $=$ $PQ=6cm$

$BC$ $=PR=9cm$

$\angle A=90°$$\angle Q=90°$

Hence, as per RHS Criterion: $△ABC\cong △$$QRP$