Question

In figure given, PQ is parallel to RS, find x.

Answer 1

Draw the perpendicular at $P$ and $R$

draw a line$MN$

$\begin{array}{c}a={120}^{\circ }-{90}^{\circ }={30}^{\circ }\\ b={140}^{\circ }-{90}^{\circ }={50}^{\circ }\\ x=180-a-b={180}^{\circ }-{30}^{\circ }-{50}^{\circ }={100}^{\circ }\end{array}$