wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In given fig. 40DCΔOBA,BOC=125 and CDO=70. Find DOC,DCO and OAB ?
1208446_4215d57947cd4ddabc74d1f074664db6.png

Open in App
Solution

OAB=OCD as they are interior opposite angles
OAB=55o
ODC=OBA=70o
BOC=125o
Finding DOC,DCO and OAB
BOC+COD=180o (as BD is straight line)
COD=DOC=180125=55o
triangle ODC sum of angles = 180o
70+55+DCO=180
DCO=180125
=55o.

1331308_1208446_ans_6703ccb13000490085f7cf960573c307.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Area of Any Polygon - by Heron's Formula
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon