Question

In $OB{r}_2,$ the bond angle is $OC{l}_2.$

• A. Greater than
• B. Equal to
• C. Less than

Answer 1

The correct option is A Greater than

The bond pair electrons in $O-X$ lie ‘more closer’ to $O$ in $OB{r}_2$ than in $OC{l}_2.$ And therefore the repulsion between bonding electrons is more in $OB{r}_2$. Moreover the size of $Br$ is bigger than $C{l}^{\prime }s.$ So $OB{r}_2$ has a greater bond angle than $OC{l}_2.$