Let ∠1=3x and ∠2=2x
Sum of angles on a straight line is 180∘.
So, 3x + 2x = 180∘
⇒ 5x = 180∘
⇒ x = 36∘ [1 Mark]
Now ∠6=∠2 [∵ ∠6 and ∠2 are corresponding angles] ⇒ ∠6=2x=2×36∘ =72∘ Hence, ∠6=72∘. [1 Mark]
In the adjoining figure, ABCD is a quadrilateral and AC is one of its diagonals. Prove that
(i) AB + BC + CD + DA > 2AC
(ii) AB + BC + CD > DA
(iii) AB + BC + CD + DA > AC + BD.
In the adjoining figure AB || CD, ∠1 : ∠2 = 3 : 2. Then ∠6 is _____