In the given figure- - A -130 degrees and degrees- If ABC is congruent to DEF- then find - F-A- 50-B- 20-C- 10-D- 130-

The correct option is C In ABC ∠A + ∠B + ∠C= 180^∘ 130 + 40 + ∠C= 180^∘ 170 + ∠C= 180^∘ ∠C= 180 170 =10^∘ Now, we know that ABC is congruent to DEF. Th ...

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Byju's Answer

Standard VIII

Mathematics

Triangle and sum of its internal angles

In the given ...

Question

In the given figure, $∠$ A= 130 degrees and $∠$ B= 40 degrees. If $△$ ABC is congruent to $△$ DEF, then find $∠$ F.

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Solution

The correct option is C

In $△$ ABC

$∠$ A + $∠$ B + $∠$ C= $180^{\circ}$

130 + 40 + $∠$ C= $180^{\circ}$

170 + $∠$ C= $180^{\circ}$

$∠$ C= 180 - 170 = $10^{\circ}$

Now, we know that

ABC is congruent to DEF.

Therefore, $∠$ C= $∠$ F (Corresponding parts of congruent triangles)

Thus, $∠$ F= $∠$ C= $10^{\circ}$

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In the given figure $∠$ AOC= $130^{\circ}$ , The value of $∠$ ABC (in degrees) is _______.

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In the given figure, ∠A= 130 degrees and ∠B= 40 degrees. If △ABC is congruent to △DEF, then find ∠F.

The correct option is C In △ABC ∠A + ∠B + ∠C= 180∘ 130 + 40 + ∠C= 180∘ 170 + ∠C= 180∘ ∠C= 180 - 170 =10∘ Now, we know that ABC is congruent to DEF. Therefore, ∠C= ∠F (Corresponding parts of congruent triangles) Thus, ∠F= ∠C= 10∘

In the given figure, $∠$ A= 130 degrees and $∠$ B= 40 degrees. If $△$ ABC is congruent to $△$ DEF, then find $∠$ F.