In the given figure find $tan A$ and $tan B$ .

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Solution

$\begin{matrix} tan A = \frac{2}{3} tan B = \frac{3}{2} \end{matrix}$

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In the given figure find tanA and tanB.

tanA=23tanB=32

In the given figure find $tan A$ and $tan B$ .

$\begin{matrix} tan A = \frac{2}{3} tan B = \frac{3}{2} \end{matrix}$