You visited us 1 times! Enjoying our articles? Unlock Full Access!

Area of a Quadrilateral

In the trapez...

Question

In the trapezium PQRS shown below, PQ is parallel to RS. Find its area.

Open in App

Solution

In ΔSAP, right-angled at A:

Also, AB = SR = 10 cm

∴ PQ = PA + AB + BQ = (9 + 10 + 16) cm = 35 cm

Now, in trapezium PQRS, the parallel sides are SR = 10 cm, PQ = 35 cm and the height SA = 12 cm.

We know that the area of trapezium is half the product of the sum of its parallel sides and the distance between them.

∴ Area of trapezium ABCD =

Suggest Corrections

Similar questions

P Q | | R S

P Q = 3 c m, R S = 7 c m

4 c m

¯ ¯¯¯¯¯¯ ¯ P Q

¯ ¯¯¯¯¯¯ ¯ S R

∠

85^{o}

¯ ¯¯¯¯¯¯ ¯ P Q

¯ ¯¯¯¯¯¯ ¯ S R

∠

70^{o}

P Q ∥ R S

= 60

P Q R S

P Q ∥ S R

P R

Q S

x

P Q = \frac{2}{3} R S

P R Q

R X S

Join BYJU'S Learning Program