In the triangle ABC

$P^{2} = Q^{2} + R^{2}$

8, 15, 17

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3, 4, 7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
8, 15, 17

Applying pythagoras theorem in the $△ A B C$
$A C^{2} = A B^{2} + B C^{2}$
AB = R, BC = Q, and AC = P
$P^{2}$ = $Q^{2}$ + $R^{2}$

Suggest Corrections

Similar questions

A B C

△ A B C

△ A B C

△ A B C, a cos A = b cos B

△ A B C

△ A B C

△ B O C

A B C,

A B = A C

∠ B = ∠ C

A B C,

∠ A B C

Join BYJU'S Learning Program