Consider the given integral,
Let, y=∫(logx)2xdx
Put,
dt=1xdx
dx=xdt
y=∫t2xxdt
y=∫t2dt
y=t33+C
where t=logx
y=logx33+C
Hence, this the answer.
Integrate the following functions. ∫(x+1)(x+logx)2xdx.