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Question

exsecx(1+tanx).dx equals

A
excosx+C
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B
extanx+C
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C
exsecx+C
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D
exsinx+C
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Solution

The correct option is C exsecx+C

To find: exsecx(1+tanx).dx

=ex(secx+secxtanx).dx

Using ex[f(x)+f(x)].dx=exf(x)+C

Here,

f(x)=secxf(x)=secxtanx

ex(secx+secxtanx).dx

=exsecx+C

Option (B) is correct.

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