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Question

[f(x)g′′(x)f"(x)g(x)]dx is equal to


A

f(x)g(x)

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B

f(x)g(x)f(x)g(x)

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C

f(x)g(x)f(x)g(x)

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D

f(x)g(x)+f(x)g(x)

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Solution

The correct option is C

f(x)g(x)f(x)g(x)


[f(x)g"(x)f"g(x)]dx
=f(x)g"(x)dxf"(x)g(x)dx
=(f(x)g(x)f(x)g(x)dx)(g(x)f(x)g(x)f(x)dx)
=f(x)g(x)f(x)g(x)


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