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Question

nx(1+nx)2dx

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Solution

lnx(1+lnx)2dx

Put lnx=tx=et

dx=etdt

=t.et(1+t)2dt

=et×1(1+t)dtet.1(1+t)2dt

=1(1+t)et+1(1+t)2etdtetdt(1+t)2

=et1+t+c

=x1+lnx+c


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